Объяснение:
(p²+pq+q²-3pq)/(p³-q³)= (p²-2pq+q²)/(p³-q³)= (p-q)²/(p-q)(p²+pq+q²)= (p-q)/(p²+pq+q²)
(6a³+48a-3a²(a+4))/(a³+64)= (6a³+48a-3a³-12a²)/(a³+64)= (3a³-12a²+48a)/(a³+64)= 3a(a²-4a+16)/(a+4)(a²-4a+16)= 3a/(a+4)
b) (y-10)9y-2)+(y+4)(y-5) = y^2-2y-10y+y^2-5y+4y-20 = 2y^2-13y-20
a) (4x-3)^2-6x(4-x) = 16x^2-24x+9-24+6x^2 = 22x^2-24x-15
b) (x-5)^2+(10x-8x^2) = x^2-10x+25+10x-8x^2 = -7x^2+25
(2+3x)(5-x)-(2-3x)(5+x) = 10+13x-3x^2-10+13x+3x^2 = 26x
дальше подставляйте значения x
Объяснение:
(p²+pq+q²-3pq)/(p³-q³)= (p²-2pq+q²)/(p³-q³)= (p-q)²/(p-q)(p²+pq+q²)= (p-q)/(p²+pq+q²)
(6a³+48a-3a²(a+4))/(a³+64)= (6a³+48a-3a³-12a²)/(a³+64)= (3a³-12a²+48a)/(a³+64)= 3a(a²-4a+16)/(a+4)(a²-4a+16)= 3a/(a+4)