y = x² - 1/lnx;
y' = (x² - 1/lnx)' = 2x + 1/(xln²x)
y=cos3x³
y' = -sin3x³·9x² = -9x²·sin3x³
y=2x-- 1 / (x * ln^2(x))
y=-9*x^2*sin(3*x^3)
Объяснение:
y = x² - 1/lnx;
y' = (x² - 1/lnx)' = 2x + 1/(xln²x)
y=cos3x³
y' = -sin3x³·9x² = -9x²·sin3x³
y=2x-- 1 / (x * ln^2(x))
y=-9*x^2*sin(3*x^3)
Объяснение:
y'=(u/v)'=1/v²[u'v-v'u] u=√(x²+1) u'=1/2√(x²+1)
v=x v'=1
y'=1/x²[x/√(x²+1)-√(x²+1)]
y'=2(cos3x+6)*(-sin3x)*3
y'=16(x³-4x²)^15*(3x²-8x)